1)\(n^{37}\equiv c\pmod {527}\)
We first find the factors of 527
527 = 17 x 31 according to this calc.
We get an equation: \(37d = 1 \pmod{480}\)
The smallest d that satisfies this equation is 37 x 13 = 1 (mod 480)
Note: 37 x 13 = 481
d = 13 ;D
2) x = 148 Same answer as Guest #1
3) 1 x 2 x 3 x 4 x 5 = 2^3 x 3 x 5
2 x 3 x 4 x 5 x 6 = 2^4 x 3^2 x 5
3 x 4 x 5 x 6 x 7 = 2^3 x 3^2 x 5 x 7
They both have a common factor of 2^3 x 3 x 5 = 120.