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Lol my bad

0= 15.3525/8-x

Hi Tertre     

Bin A  has one white ball and four black b***s.

Bin B  has three b***s labeled $1 and one ball labeled $7 . 

Bin W has five b***s labeled $8 and one ball labeled $500. 

A game is played as follows: a ball is randomly selected from bin A . If it is black, then a ball is randomly selected from bin B ;otherwise, if the original ball is white, then a ball is randomly selected from bin  W. You win the amount printed on the second ball selected. What is your expected win?

I am not very familiar with expected wins but this is what seems sensible to me.

If you choose a ball from bin B then the average win would be    (3*1+7)/ 4 = $2.50

If you choose a ball from bin W then the average win would be    (5*8+500)/6 = $90

so the answer would be   (4/5  *  $2.50) + ( 1/5  *  $90)  =   $2 + $18  = $20

I would expect to win $20       

( The expected win is the average win you would get if you played the same game an infinite number of times )

Assuming your chocolate coin are circular, then we have:

Area =r^.Pi

A = (4/2)^2 . Pi=4 x 3.141592 =12.57 cm^2

A = (3/2)^2 . Pi=2.25 x 3.141592 =7.07 cm^2

7.07 x 2 =14.14 cm^2

So, the two 3-cm diameter are larger than the single 4-cm diameter by:

14.14 - 12.57 =1.57 cm^2

[8+6]C6 =3,003 ways? Not certain about having "more girls than boys"!!.

This needs an equal sign in the equation to 'solve for 'x' '

something like   15.3525/8  - x = 33  

= 6.4 / 4   x  10^(-4)/10^6   =  1.6 x 10^(-4 -6)  = 1.6 x 10^(-10)

3 ways:

6 girls and 0 boys/6 students

5 girls and 1 boy/ 6 students

4 girls and 2 boys/ 6 students

Solve for x:
(4 x^2)/3 = 1

Multiply both sides by 3/4:
x^2 = 3/4

Take the square root of both sides:
Answer: |x = sqrt(3)/2          or            x = -sqrt(3)/2

Huge thank you. You already did a whole lot!

Oops...sorry......LOL!!!

Here it is....http://pennance.us/home/downloads/3018/image.pdf

If I can figure this out.....I'll see if I can help you....

There does not seem to be any link there haha

Sorry, Tony.....I'm  not familiar with images of a function....

Here's a resource that might help you.....

are u there cphil

what is 36 x 3/4

\(36 \times \frac {3}{4}= \frac {36 \times 3}{4} = 27\)

!

Nice!

Now I get it!

Thanks a lot!

You have any idea how one would find Ima f(x) ?

if i have 1 chocolate coin that measures from one side of the coin to the other 4 cm and i also have two chocolate coins that measure 3 cm from one side to another tell me witch is bigger the one chocolate coin or the two smaller ones

A1 = (4² * π / 4) = 16 * π / 4

A2 = 2 * (3² * π / 4) = 2 * 9 * π / 4 = 18 * π / 4

A2 > A1

The two chocolate coins are together more than the larger chocolate coin.

!

Remember that, at an x intercept, y = 0

So......if we plug 0 into the function, we get

y = 4 - sqrt [16  + 6(0)  - 0^2 ]  =

4 - sqrt (16)  =

4 - 4  = 0

This shows that x = 0 must be a root  [ i.e., an x intercept ] because when we plug this value into the function we get y = 0 back

Likewise....putting  x = 6 into the function we have

y = 4  - sqrt [ 16 + 6(6)  - 6^2 ]  =

4  - sqrt [ 16 + 36 - 36 ] =

4 - sqrt [ 16]  =    

4 - 4 = 0     so    x = 6 must also be a root [ i.e., an x intercept ]

Remember something else......if  a * b   = 0    then either a = 0  or b = 0   or they both equal 0

So....if we have   x ( -x + 6)  = 0 , then either  x = 0  or  -x + 6 =0 

And we needed to solve both to find out what makes each factor equal to 0

(–5) • (7) – (6) • (–2)  =   perform the multiplications before the subtraction

-35 - (-12) =

-35 + 12  =

-23

But that's exactly what I don't get.

If you set x=0 wouldn't that mean:

0=0(-0+6)   ?  cause that's = 0

I don't get how you can end up with x=6

Like how did you go from 0=x(-x+6) to 0= -x + 6

(1/2) (2/3)  =  2/6   =  1/3

x(-x+6)=0

Setting both factors  to 0 , we have

x = 0         and      -x + 6 = 0

The first is obvious

For the second, we have

-x + 6 = 0     add x to both sides

6 = x

These are the two x intercepts  at x = 0 and x = 6

It's asking you to show that g(x) is it's own inverse

Fof g(x), write  y   and we have

y = ( x + 1) /(x - 1)     the object is to first get a single x by itself......multiply both sides by  x - 1

y ( x - 1)   =  x + 1

yx - y = x + 1       rearrange as

xy - x = y + 1       factor out x on the left

x(y - 1)  = y + 1    divide both sides by y - 1

x = [ y + 1 ] / [ y - 1]       "exchange" x with y

y = [x + 1 ] / [x - 1]     and for y, write g^-1(x)

g^-1(x) =  [x + 1 ] / [x - 1]     notice that this is the same as g(x)

y = ∛x    

To find the x intercept, let y = 0

0 = ∛x     cube each side

0 = x     so, wehave the point (0, 0)

To find the y intercept,let x = 0

y = ∛0   = 0

So........again we have the point (0,0).....thus the x and y intercepts are the same, i.e., the origin

I don't understand this part:

x(-x+6)=0

Setting both factors to 0? Does that mean :

x=0

0(-0+6)=0

0=0

and then 

x=6

6(-6+6)=0

-36+36=0

(gives coords x=0 y=0 too)

By the way huge thanks for the help!

much appreciated, pavlov :)