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Nothing unusual here....

example     4x  *  1/3   =  4x/3

                   4x *  2/5   =   8x/5

First , calculate the sqrt(99) = 9.95

pi^2 = pi x pi = 3.14 x 3.14 = 9.87

    and you are given              9.8

SO the smallest is   9.8    the next greater is  9.87  (pi squared)   and the greatest is 9.95

This is a well known problem called the "Monty Hall" problem.  Have a look at https://en.m.wikipedia.org/wiki/Monty_Hall_problem for example.

(switch).

....or you can just factor it:

35-b^2 = 2b          add  'b^2 - 35 ' to both sides

0=b^2 + 2b - 35

(b+7)(b-5) = 0        Now either  b+7   or  b-5  (or both) = 0   so b = -7 or 5

This is \(\frac{6.4\times10^{12}}{1.6\times10^3}=4\times10^{12-3}\rightarrow4\times10^9\)

THAT is a REALLY big subject......do you have something specific to ask ?

These raise a number to a power. So for example, entering 2 x³ = results in 8,

entering 2 x² = results in 4, and entering 2 x^y 5 = results in 32

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Use the "2nd" key, top left.

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"e" in the top left hand corner is also used to mean "exponent", when entering large numbers such as:  1.25 x 10^25 =1.25e25, which is computer language for "scientific notation".

Use the AP formula:(2F + D(N -1)) x (N/2) =((2*-10) + 1*(100 -1)) * (100/2)=                                      (-20 + 99)*50=79*50=3,950

2/3(6h-9)=6

\({\color{red}\frac {2}{3} \times (6h-9)=6}\) 

 \(6h-9= 6 \times \frac {3}{2}\)    

\(h=\frac{9+9}{6}\) 

\({\color{Blue}h=3}\)              

\({\color{red}\frac {2}{3 \times (6h-9)}=6} \)

 \(2= 6\times 3 \times (6h-9)\)

\(6h-9= \frac{2}{6\times3}\)

\(h=\frac {\frac{1}{9}+9}{6}\)

\({\color{Blue}​h=\frac{82}{9\times 6}=\frac{41}{27}}\)        

asinus :- ) !

Sorry guest but your answer is not correct

For starters,     0.25*0.2 = 0.05   NOT    0.5

How does 1,25 * 1,2 = 1,5 How does it become 1,5

\(1.25\times 1.2 \\ =(1+\frac{1}{4})\times 1.2\\ =1\times 1.2 + \frac{1}{4}\times 1.2\\ = 1.2 + \frac{1.2}{4}\\ = 1.2 + 0.3\\ =1.5\)

1300

Thanks :D

1*1 = 1

0.25 * 0.2 = 0.5

1 + 0.5 = 1.5

You can think about 25*2=50

Hello, good morning Mormert!

35-b^2=2b      b = ?

The general form of a quadratic equation is

ax² + bx + c = 0

x is calculated using the equation solution

\({\color{Blue}x = {-b \pm \sqrt{b^2-4ac} \over 2a}}\)

Put the equation in the general form.

35-b²=2b

-b² - 2b + 35 = 0          Replacing b = x

-x² - 2x + 35 = 0

ax² + bx + c = 0

a=-1  b=-2  c=35

\({\color{Blue}x = {-b \pm \sqrt{b^2-4ac} \over 2a}}\)

\({\color{Blue}x = {-(-2) \pm \sqrt{(-2)^2-4*(-1)*35} \over 2*(-1)}}\)

\({\color{Blue}x=\frac{2\pm \sqrt{144} }{-2} = \frac {2\pm12}{-2}}\)

x₁ = - 7

x₂ = 5            

Swap back x b

b₁ = - 7

b₂ = 5              !

I hope I could help you.

asinus: -)!

to number 1)

1.   For the function f(x)=-4(sqrt x-1), find the inverse function and x.

2. The function f(x)=(x-1)^2 - 4 is not one-to-one. If you restrict the doamin for f(x) to x≤1, what is its inverse function and the domain for the inverse?

e, also called Euler's number, is a mathematical constant that is used in calculus and natural logarithms. It is approximately equal to 2.72. You can probably learn more about it with a quick Google search if you search 'Euler's number'

The square root button is to the left of the x² button. It looks like a checkmark with an x next to it.