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27$+7,75%

27$=100%

0,27$=1%

2,0925$=7,75%

27$+2,0925$=29,0925$=29,10$

Are you dealing with VECTORS and want to know the VELOCITY?

If you just want the SPEED it is   Distance/Time = (30+15+15 miles) / (1/2 hr) = 60 /  1/2  =  120 MPH

120 mph

2.     IS a decimal form

2+6+7+9=24

3.482 x 10^9

5.3 x 10^0     or just   5.3

thx

Find the least common multiple:
lcm(65, 120)
Find the prime factorization of each integer:
The prime factorization of 65 is:
65 = 5×13
The prime factorization of 120 is:
120 = 2^3×3×5
Find the largest power of each prime factor.
The largest power of 2 that appears in the prime factorizations is 2^3.
The largest power of 3 that appears in the prime factorizations is 3^1.
The largest power of 5 that appears in the prime factorizations is 5^1.
The largest power of 13 that appears in the prime factorizations is 13^1.
Therefore lcm(65, 120) = 2^3×3^1×5^1×13^1:
Answer: |lcm(65, 120) = 1560

what percentage is 2,200,000 of 7,400,000,000

2,200,000 / 7,400,000,000 =0.0002973 x100 =0.02973%

5/8 = .625   you are both incorrect.    Now  EIGHT divided by FIVE   IS   1.6

3-3*6+2 = 3 - 18 +2 = -15 +2 = -13     You have to do the MULTIPLICATION first , then the addition or subtraction.

6.25 x 10^2

There are 1000 billions in a trillion , so multiply by 1000

3,730 Billion

(3x + 4)(2x - 2)=6x²-6x+8x-8=6x²+2x-8

What is 7.854 converted into a decimal when the 54 is repeating?

7.854545454...... =7 47/55 converted to a mixed FRACTION!!.

\(\frac{7}{4}:\frac{2}{5}=\frac{7}{4}*\frac{5}{2}=\frac{35}{8}=4\frac{3}{8}\)

y=0.25t+0.75

A car brought for £22000 depreciates in value by 8% each year. After how many years is the car worth less than half of it's original value?

these are all just turn the equation's denominatior to the CM (common multiple) or you could just use the LCM (least Common multiple), so 7 in the 4/7 and the 14 in 3/14 then multiply both by each other, so you will get 98. Then, multiply 4 by 14, and 3 by 7, so you will now get 56/98 and 21/98, then add to get  77/98. 

A car brought for £22000 depreciates in value by 8% each year. After how many years is the car worth less than half of it's original value?

1 - 8% =92%

11,000 =22,000 x (0.92^n) divide both sides by 22,000

1/2 =.92^n take the log of both sides

n =Log(1/2) / Log(.92)

n=8.31 years - Just over 8 1/3 years, the car will be worth LESS than 1/2 its original value.

0.297297297297%

    x         =    8

22000       100

22000*8 = 176000

176000/100 = 1760

22000-1760 = 20240

Then, keep doing this until the number is half of 22000 or less, but the number will always be less when you find the %, so you will have to keep doing      x                                                                   8

                                                Solution of the number you just got    =       100

Then, multiply the number you just got and multiply it by 8 then divide by 100 then subtract it by the number before solving the equation, and keep doing this until you get at least less than 22000.

-7<x+2/4

-2/4  -2/4

-7 2/4<x

or 

-7 1/2<x

or 

-15/2

2^-2