LOL :P
:)
Btw I think it has already been a few days ago when I last logged into the forum?
I didn't leave the forum :)
You are just showing off Max LOL
Good for you Max :)
Good question though.
\(\text{Let }x = 1991\\ \dfrac{1}{1991} + \dfrac{1992\times 1990}{1991} - 1992\\ = \dfrac{1}{x} + \dfrac{(x+1)(x-1)}{x}-(x+1)\\ =\dfrac{1}{x} + \dfrac{x^2 - 1}{x} - (x+1)\\ = \dfrac{x^2 +1 - 1}{x }-(x+1)\\ = \dfrac{x^2}{x} -(x+1)\\ = x - x - 1\\ = -1\)
Substitution is always brilliant :)
1 loaf of bread = 1/4 cup of oil.
5 loaf of bread = 5 x 1/4 cup of oil = 1 1/4 cup of oil.
There are still 5/8 cup of oil left
Therefore add them up: 1 1/4 + 5/8 = 1 2/8 + 5/8 = 1 7/8
Judy started with 1 and 7/8 cups of oil.
\(m(z+9) - m(z) ; m = z^2\\ = (z + 9)^2 - z^2\\ = z^2 + 18z + 81 - z^2\\ = 18z + 81\)
You mean the A 'flat' 9 sus4 chord? :)
I do know something about music :)
Hello Melody:The question about $50,000 annuity for Life? That was not my question, sorry. I did look at it and I understand what you did there. I believe this question of mine is more involved, because the parents continue to make payments to the fund while the son is going and withdrawing his $25,000 at the beginning of each year. So, the two have to balance just right. If their payment were only for the first 10 years, then it would be relatively easy and simple to get the right answer. I have tried several ways of getting the right answer but it just doesn't balance. Thank you for looking at it.
2x2+20x+50=0
Based on input of -6, 3 and 5 for a, b, and c respectively, what will be displayed?
It will be displayed: a + b + c = 4
5(-x^2tan^2(x)+sec(x)cos(x)(x^2sec^2(x)+2xtan(x)))/(sec^2(x)cos(x)) if x=5
\(\frac{5 ( -x^2tan^2(x) + sec(x)cos(x) (x^2sec^2(x)+2xtan(x)) ) }{ (sec^2(x) cos(x))} \\ =\frac{5 ( -x^2tan^2(x) + 1 (x^2sec^2(x)+2xtan(x)) ) }{ \frac{ cos(x)}{cos^2(x)}} \\ =5cos(x) ( -x^2tan^2(x) + x^2sec^2(x)+2xtan(x) ) \\ =5cos(x) ( -x^2*\frac{sin^2(x)}{cos^2(x)} + x^2*\frac{1}{cos^2(x)}+2x\frac{sin(x) }{cos(x)} ) \\ =5cos(x) ( -x^2*\frac{sin^2(x)}{cos^2(x)} + x^2*\frac{1}{cos^2(x)}+2x\frac{sin(x) }{cos(x)} ) \\ =5cos(x) ( x^2*\frac{1}{cos^2(x)} -x^2*\frac{sin^2(x)}{cos^2(x)}+2x\frac{sin(x) }{cos(x)} ) \\ =5cos(x) ( x^2[\frac{1}{cos^2(x)} -\frac{sin^2(x)}{cos^2(x)}]+2x\frac{sin(x) }{cos(x)} ) \\ =5cos(x) ( x^2*1+2x\frac{sin(x) }{cos(x)} ) \\ =5x^2cos(x) +10xsin(x) \\ When \;\;x=5 \qquad \text{is that radians or degrees?}\\ =125cos(5) +50sin(5) \\ \)
On the web2 calc it is xy
on other calcs it could be ^
Do you seriously expect anyone to look at your questions when you ask in such a derogatory way?
log 10 (base 10) is 1 ??
\(9 log x = 2\\ logx=2/9\\ x=10^{(2/9)}\\ x=100^{1/9}\\ x=\sqrt[9]{100} \)
What would you get stuck on?
Is your graph related to sticky tape, or maybe glue ????
A rational number is one that can be expressed as a fraction. They can also be expressed as a terminating or recurring decimal.
Numbers that are NOT rational (irrational numbers) include pi and sqrt2
|4x+1|-2>-5
|4x+1|>-3
this will always be true because the LHS must be greater or equal to zero - it is an absolute value, it cannot be negative.
\(x \in R\)
both a square no means
Did you work through the last answer that I did for you a couple of hours ago?
You did not make any comment. .....
I was fairly similar to this one. Try to start it on your own and show us what you have done.
It means 2 raised to the power of t
2^t = 2t
