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Idk

Maybe you define f(x) = -e^(x+3)-4 ;D

But 2nd one don't know sry......

mAB

= 2/(2+3+4) * 360 deg

= 80 deg

mBC

= 3/2 * mAB 

= 120 deg

mCA

= 4/3 * mBC

= 160 deg

idek how to solve m angle A,B,C from just these informations..... sry......

Here is a picture to go with Max's answer: 

??

What do you mean by this?

Window XP does not suck it can do 2^100 and show the answer properly and not using scientific notation......

Personally love Window 7 though XD

8^2 - 2^2

= 64 - 4

= 60 :D

The first sentence indicate that the width of the rectangle = 2 x 6 = 12.

2nd sentence indicates that length = 10 + 6 + 6 = 22

Area = 22 x 12 = 264

Who would win tough match

The surface area of this thing is just a 3 x 3 x 1 box surface area minus 2 faces because there are still squares in the hole.

Surface area 

= (3 x 3) x (3 x 3) x 2 + 3 x (3 x 3) x 4 - 2 x 3 x 3

= 252 square centimeters

Let's call the unknown scale factor "s'"..

1s + 2s + 4s + 5s = 360º

Solve for s.

12s = 360º

s = 30º

So...

a. m arc PQ = 1s = 1(30º) = 30º

b. m arc QR = 2s = 2(30º) = 60º

c. m arc RS = 4s = 4(30º) = 120º

d. m arc SP = 5s = 5(30º) = 150º

e. m∠S = (1/2) * (m arc PQ + m arc QR) = (1/2) * (30 + 60) = 45º

f. m∠Q = (1/2) * (m arc RS + m arc SP) = (1/2) * (120 + 150) = 135º

g. m∠R = (1/2) * (m arc PQ + m arc SP) = (1/2) * (30 + 150) = 90º

h. m∠P = (1/2) * (m arc RS + m arc QR) = (1/2) * (120 + 60) = 90º

*edit* added ºs :)

So ill do more

youll gotta like the picture too you know

Noice.

Melody may put this post into the Sticky topic like mine!!

My post teaches new members how to use LaTeX!!

Great job on doing this :D

~The smartest cookie in the world.

Use Pythagoras theorem to find the lengths of blue lines. 

Total length

= 4/2 + 6/2 + 8/2 + \(\sqrt{(\dfrac{4}{2})^2+(\dfrac{6}{2})^2}+\sqrt{(\dfrac{8}{2})^2+(\dfrac{4}{2})^2}+\sqrt{(\dfrac{6}{2})^2+(\dfrac{8}{2})^2}\)

= 2 + 3 + 4 + \(\sqrt{13}\) + \(2\sqrt{5}\) + 5

= 14 + sqrt(13) + 2sqrt(5)

8k/2 = 12.5% * 8 * 9

4k = 9

k = 2 1/4 :)

I'm confused. What is so important about the number 19? 7UR7L3M4N☢🐢☣

NO! THIS PERSON KNOWS TOO MUCH!!! 7UR7L3M4N☢🐢☣

a. m∠AOD = m arc AD = 35

b. DO bisects ∠AOB, so m∠DOB = m∠AOD = 35 = m arc DB

c. m∠AOD + m∠DOB + m∠BOC = 180

    35 + 35 + m∠BOC = 180       → m∠BOC = 180 - 35 - 35 = 110 = m arc BC

d. m∠A + 90 + m∠AOD = 180

   m∠A + 90 + 35 = 180     → m∠A = 180 - 90 - 35 = 55

e. m∠C = (1/2) * m arc BA

   m∠C = (1/2) * (35 + 35) = 35

f.  Since m∠AOD = m∠C , DE is || to BC... and so m∠AFO = m∠B = 90

g. m∠COE = m∠AOD = 35 = m arc CE

h. m arc AE = 180 - m arc CE = 180 - 35 = 145

Looks like my answers agree with yours!

Also I checked your number 8 and I agree with all your answers for it! 

.

For 9b: Since you already know that DC is 145 and BC is 110, subtract to get DB

For 9e: I'm not sure if you've already learned this, but there is a formula that every angle formed from a point on a circle and two points on opposite ends of a diameter is a 90 degree angle. You can probably look it up to get a proof if you need one. So, that makes angle ABC 90 degrees. Therefore, BAC and ACB add up to 90 degrees, and since BAC is 55 you know that angle C is 35.

For 9f: As aforestated in 9e, 90 degrees. I don't have the proof memorized, but you can look it up.

For 9g: You know what AD is, and because of the Vertical Angles Theorem both angles DOA and COE  are the same size, meaning that arc CE is the same length as AD.

For 9h: This is 180 degrees minue CE.

Hope this was helpful! :)