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I get 19.41 for the total perimeter  (sorry didn't see that in your last post).....

Learning is sometimes difficult....But all of a sudden it will go "CLICK" !.    Hang in there..

I'll show you how to do the first part of the perimeter....I'll do the longest side

  two points   (x1 y1) and (x2 y2)   are (-1,5) and (5,1)   right?   

Use the formula:  d^2 = (x1-x2)^2 + (y1-y2)^2

                                    = (-1-5)^2 + (5-1)^2

                             d^2 = (-6)^2  +  (4)^2 

                             d^2 = 36 + 16

                              d^2 = 52

                              d= sqrt(52) = 7.21 units   (for ONE side of the perimeter)

See how I did that?    Now you do it for the opposite side     (3,7)  and (-1,5)       Then we will be half way....

    try it and let me know what you get.....

Is the perimeter 19

Oh my god im literally crying and freaking out rn because I CANT FREAKING GET THIS IM SO FREAKING STU PID!!!!!!!!!!!!!!

So how exactly do I do this, I got the area which is 21 and now how do i get the perimeter

AB

DA

DC

and CB?

Exactly !    7     Now you can calculate the areas of both of the triangles   (1/2 b * h )   then add them together....

Voila !    You have the area of the composite figure.......

Now let's start work on the perimeter.....

Distance between two points on the coordinate plane   d^2 = (x1-x2)^2 + (y1-y^2)^2     (remember?)

You might have to do it FOUR times for this figure....   Go!

Nevermind

This scan may be a bit clearer.....   Cowgirl Up !   as they say....don't stress...you can do this.....I am not going to do it for you, but I'll help you through it........it will become easier as YOU work tyour way through it.....go !

Ohh 7? 

Very close.....but check that '6' dimension !   

I didn't mean to sound rude, I'm just super stressed right now. Problem is I don't know the height or base of the triangles.

Would one triangle be 1/2*6*2

and the other 1/2*6*4 or am I completely wrong

Higher up in this thread I posted how to find the area of a triangle....

    there is actually only TWO triangles of concern in the scan I posted......the lines marked 'H' are just to show the dimensions for 'Height'......   You CAN do it......  And you don't need the perimeter to calculate the area....(though I do understand you have to find the perimeter per the question)

5(2a-2)=7(a+8)-27   Use distributive property

10a-10 = 7a+56 - 27       Add 10 to both sides

10a  =  7a + 56- 27 + 10    Subtract 7a from both sides

10-7a = 56-27+10              simplify

3a = 39                          divide both sides by 3

a = 13

Hyperbola C2:  \(\frac{(x-a)^2}{9}-\frac{(y-0)^2}{4}=1\)

On the x-axis y = 0, and the values of x are: \(x = a\pm3\) so \(x=a\) is the value half way between the two parts of the curve.

The two asymptotes cross at this half-way point, so from \(y=\frac{2}{3}x-2\) we have \(x = 3\) when y = 0.  

So \(a = 3\)

I'm sorry i'm not as smart as you. I do know how to find the area of a triangle but I haven't even gotten the perimeter yet. Also you said 2 triangles and that is 4.

We have eight pairs.

{0, 7} {1, 6}{2, 5} {3, 4} {4, 3} {5, 2} {6, 1} {7, 0}

However, {0, 7} doesn't work because 7 is just a one digit number, so we have \(8-1=7\) total possibilities. You were right!

You are very welcome!

:P

It is a good, new day today.

With one cut, we get the fabric split in two.

With two cuts, we get the fabric split in three, and so on.

\(\frac{20}{2}=10\) so there are 10 pieces of fabric, which result in \(10-1=9\) cuts.

You are very welcome!

:P

I'm fine, thanks!

It depends on the calculator. A TI-84 plus ce is a good and there are ones these: https://www.mathway.com/Algebra

https://www.symbolab.com/