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Those potatoess! thanks a lot for your time! you was clear as potato... no as Diamond! keep do your good job math sensei!

Have a nice day! 

thanks again!

Thanks!!

2000 potatoes at 84 euro each  is 90000 euros         (my goodness they are expensive potatoes!)

X  potatoes at     45 euros is             45X     euros

Now we have  2000+X  potatoes.  And we want them to have an average price of  69 euros

So the total cost of all the potatoes will have to be     69(2000+X)    euros.

so we have

\(2000 \times 84  + 45x = 69(2000+x)\\ 2000 \times 84  + 45x = 69\times 2000+69x\\ 2000 \times 84  -69\times 2000 = 69X-45x\\ 2000(84-69)=(69-45)x\\ x=\frac{2000(84-69)}{(69-45)}\\ x=\frac{30000}{24}\\ x=1250 potatoes\\ \)

check

(2000*84+1250*45)/3250 = 69   Good :)

So what do we have 

\( x=\frac{2000(84-69)}{(69-45)}\\ \)

Let the original number of units be N     So  N=2000 potatoes

Let the original highher price be      H    so  H=84 euros

Let the new low price be       L                so L = 45 euros

Let the desired average price be A        so A= 69 euros

x is the additional number we need to buy to reduce the average price to the one that is desired.

and we have:

\(x=\frac{N(H-A)}{A-L}\)

Hello again

sat is dividend of bitcoin.

OK forget about crypto lets do this with simple staff potato and currency euro

i have a sell order 2000pcs at the price of 84 euro thats give me 168000 euro!

the current price of potato is 45 at the moment so i want to average down the potatos of price at 84 euro! 

IF i buy 2000pcs of potato at 45 this is 90000 cost, so the average price of all together 4000 potatos is 64.5 euro if i put those for sell will return me back 168000euro + 90000euro= 258000 euro!

BUT i dont want to put them on 64.5 euro price i want a SPECIFIC PRICE of 69 euro per potato, so i want a formula to find how many potatos i must buy at current price of 45euro to average down the 2000 potatos of 84euro price to 69euro!

i try to be clear as i can and sorry for my bad english

thanks in advance.

In a chess variant, a "lord" can move one space at a time, either upward, or to the right, or diagonally up and to the right.

How many ways are there for a lord to move from the bottom left to top right corner of the 8 by 8 chessboard?

\(\begin{array}{|c|c|c|c|c|c|c|c|} \hline 1 & 15 & 113 & 575 & 2241 & 7183 & 19825 & \mathbf{48639} \\ \hline 1 & 13 & 85 & 377 & 1289 & 3653 & 8989 & 19825 \\ \hline 1 & 11 & 61 & 231 & 681 & 1683 & 3653 & 7183 \\ \hline 1 & 9 & 41 & 129 & 321 & 681 & 1289 & 2241 \\ \hline 1 & 7 & 25 & 63 & 129 & 231 & 377 & 575 \\ \hline 1 & 5 & 13 & 25 & 41 & 61 & 85 & 113 \\ \hline 1 & 3 & 5 & 7 & 9 & 11 & 13 & 15 \\ \hline \mathbf{1} & 1 & 1 & 1 & 1 & 1 & 1 & 1 \\ \hline \end{array} \)

The inactive accounts were not deleted.

How do I know?

Rosala's back.

And she was inactive for QUITE a long time...

The Upload thingy is bothering me the most... what about you?

Don't know.....but you're correct  !!!

ahhhh 

ok I got it.

what yelling?

I do agree, CPhill and Hetictar and basically all the people here are DA BEST

Hey CPHILL

why is a ton of stuff going cra-z on Web2.0 calc nowadays?

Well....I'm not sure what  the slots are supposed to represent...but

If the first slot is the coefficient on x^3....then it would be  (1)

Similarly...on x^2 we have (-5)

And on (x)  we have  (-2)

What reamains unclear  is the "slot" for the constant term....this would be  (24)

Hope that helps

for the first one how would insert it in the three slots?

Answered here :

https://web2.0calc.com/questions/help_28801

The "forgot password" thingy is still there....just not obvious

If you hover your cursor just below  the password box, you will see the "forgot password" tab

See if you can use that to log in, DS  ....

Here's  what I come up with :

See the following image : 

Let the intersection point of the bisectors  = E

Let angle CAB  =x   angle ABC = y    angle ACB = z     angle DBC  = (180-y)/2

angle EAB  = x/2     angle ABE =  y+ (180-y)/2 

So we have two triangles  ABC   and  AEB

So in ABC .....x + y + z  = 180       (1) 

And in  AEB  .....x/2 + 50 + y +  (180-y)/2=180     (2)

We can simplify (2) as follows :

x/2 + (180-y)/2 + y  = 130        multiply through by 2

x +  180-y + 2y  =260

x + y  =  80   (3)

Subbing (3) into (1) we have that

(80) + z  =180

z = 100  = angle ACB  = angle "C"

Which matches your result, CU   !!!!

\(\text{Here's a bit of a derivation of the monthly payment}\\ \text{ignore months and years for a moment and just let $r$ be the periodic rate}\\ \text{$n$ will be the number of periods. Let $\alpha = (1+r)$}\\ \text{every period we take the principal, apply interest, and subtract a payment}\\ p(k+1) = \alpha p(k) -pmt,~p(0) = loan\\ \text{If you work through this you find that}\\ p(n) = \alpha^n loan - pmt \sum \limits_{k=0}^{n-1} \alpha^k = \alpha^n loan - pmt\dfrac{\alpha^n-1}{\alpha -1}\)

\(\text{We want $p(n)=0$ and we need to solve for $pmt$}\\ \alpha^n loan = pmt \dfrac{\alpha^n -1}{\alpha-1}\\ loan = pmt \dfrac{1-\alpha^{-n}}{\alpha -1}\\ pmt =loan \dfrac{(\alpha-1)}{1-\alpha^{-n}} = loan \dfrac{r}{1-(1+r)^{-n}}\)

\(\text{Here we plug in $loan=1600000,~n=360,~r=\dfrac{0.03}{12}=0.0025$}\\ pmt = \$1600000\dfrac{0.0025}{1-(1.0025)^{-360}} = \$6745.66\)

The total cost after tax to repair Deborah’s computer is represented by 0.08  (50h)+50h , where h represents the number of hours it takes to repair Deborah’s computer. What part of the expression represents the amount of tax Deborah has to pay? Explain.

Found my old page so my account is still in here: https://web2.0calc.com/members/dragonslayer554/

are you sure you typed it correctly? What is 0.08 50 50 ( h h ) +

same! everything says internal server error!!!
 

Its causing the website to go haywire its so annoying!!!

also there's an internal server error so nothing works