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Now I'm not an expert, you can search it up.

I expect to eat a lot of carbs. And sure, potassium and electrolytes and sodium could help, maybe electrolyte water and orange juice?

You're welcome!

:P

-6776, use the calculator.

You are very welcome!

:P

Can you find the equation of the red line?

It has a slope of 3/2 and a y-intercept of -7/2.

Can you solve from there?

You are very welcome!

:P

Welcome, DC  !!!

7x^5  + 49x^2  + 28x    take out the GCF

(7x )  ( x^4 + 7x  + 4)

nice man thanks 

Density  =  Mass / Volume   ....  so  .....

Volume  =  Mass / Density

Volume  =   5.32 kg  / [ 5.34 g / cm^3]                { 5.32kg  = 5320 g }

Volume   =   5320 g  * cm^3  / 5.34 g

Volume  ≈  999.25  cm^3

The points (3, 1)  and (1, -2)   are on the graph

The slope of the line through these points is given by :   [-2-1] / [ 1 - 3]  = -3/ -2  = 3/2

So.....the equation of this line is

y  = (3/2)(x - 3) + 1           multiply through by 2

2y =  3( x - 3)  + 2

2y = 3x - 9 + 2

-3x + 2y  = - 7             multiply through by -1

3x  - 2y  =  7

Since we have a dotted line than we have that either

3x - 2y  > 7        or         3x - 2y  <  7

Note that (0, 0)  is in the shaded area....this will satisfy   3x - 2y   < 7

x^3  +  2x^2  +  5x + 10

x^2( x + 2)  + 5(x + 2)

(x + 2) (x^2 + 5)

\(\beta=3+2i\\ \alpha+\beta=k \qquad k\in R\\ so\\ \alpha=n-2i\\ \alpha-2\beta=wi \qquad w\in R\\ (n-2i)-2(3+2i)=wi\\ n-6-2i-4i=wi\\ (n-6)-6i=wi\\ n-6=0\\ n=6\\ \alpha=6-2i \)

I think I made that more complicated than necessary.

\(\text{in a frictionless system linear momentum is conserved}\\ 15.0 + (-35.0) = (-12.0) + m_{bf}\\ m_{bf} = -8 kg*m/s\)

physics help

a. mg

\(\begin{array}{|rcll|} \hline && 6.0\times 10^3\ kg \times \dfrac{1000\ g}{1\ kg} \times \dfrac{1000\ mg}{1\ g} \\ &=& 6.0\times 10^3\times10^3\times10^3\ mg \\ \mathbf{6.0\times 10^3\ kg} &=& \mathbf{6.0\times 10^9\ mg} \\ \hline \end{array} \)

b. Mg

\(\begin{array}{|rcll|} \hline && 6.0\times 10^3\ kg \times \dfrac{1\ Mg}{1000\ kg} \\ &=& 6.0\times 10^3\times \dfrac{1}{10^3}\ Mg\\ \mathbf{6.0\times 10^3\ kg} &=& \mathbf{6.0\ Mg} \\ \hline \end{array}\)

The expression \(a(b - c)^3 + b(c - a)^3 + c(a - b)^3\) can be factored into the form

\( (a - b)(b - c)(c - a) p(a,b,c)\), for some polynomial \(p(a,b,c)\). 

Find p(a,b,c)

\(\begin{array}{|rcll|} \hline a(b - c)^3 + b(c - a)^3 + c(a - b)^3 &=& -a^3b + a^3 c + a b^3 - a c^3 - b^3 c + b c^3 \\ (a - b)(b - c)(c - a) &=& -a^2b + a^2 c + a b^2 - a c^2 - b^2 c + b c^2 \\ \hline -a^3b + a^3 c + a b^3 - a c^3 - b^3 c + b c^3 &=& (-a^2b + a^2 c + a b^2 - a c^2 - b^2 c + b c^2)(a+b+c) \\\\ &=& -a^3b + a^3 c + a b^3 - a c^3 - b^3 c + b c^3 \\ && +a^2b^2-a^2b^2 \\ && +a^2c^2-a^2c^2 \\ && +b^2c^2-b^2c^2 \\ && +a^2bc-a^2bc \\ && +b^2ac-b^2ac \\ &&+c^2ab-c^2ab \\\\ \mathbf{a(b - c)^3 + b(c - a)^3 + c(a - b)^3} &=&\mathbf{ (a - b)(b - c)(c - a)(a+b+c) } \\ \hline \end{array}\)

\(\mathbf{p(a,b,c) = a+b+c} \)

Help please
\(\text{Find the value of } x = 1 + \cfrac{1}{2 + \cfrac{1}{2 + \cfrac{1}{2 + \cfrac{1}{2 + \ddots}}}}.\)

Thank you, CPhill !

This LITERALLY is your homework... 

and you are LITERALLY asking us to help you cheat homework.

\_.o._/

I misunderstood the question; I'm totally wrong! 

I do not like thee, Doctor Fell,
The reason why I cannot tell;
But this I know, and know full well,
I do not like thee, Doctor Fell.

but whooooo are youuuuuu?  

A statement like that is pretty much useless when it's anonymous. 

Determine the distance between -7 and 7.

Well, this one you could simply count along the line. 

There's plus seven to get from –7 to 0, then plus seven to get from 0 to +7.  That's a total of fourteen.  Answer D.

.

I've don it differently, but got the same answer.

I connected D and 2 in order to form a right triangle.

BD = 2.5      B2 = 2

D2² = BD² - B2²

D2 = 1.5

Area of a triangle ABD =  D2 * B2 = 3

(AD)² * pi = circle area       Area = 19.635 n²

{(19.635 / 360 ) * 106.26} - 3 = 2.795 n²     

On a number line, the coordinate of point A is −235, and the coordinate of point B is 145. What is the length of AB?

145  - (-235)  =

145 + 235  =

380  units

A fruit stand owner has 90 apples and 72 oranges. He wants to make the greatest number possible of identical bags with a combination of apples and oranges without any fruit leftover. How many apples are in each bag?

18  is the greatest common denominator between  72  and 90

So  we can have    18  bags   and each will contain

72/18  =  4  oranges      and

90/18  =  5 apples

Last one

-3 3/4, -3 13/20,-3 -17/25, -3 3/5

-3 75/100     -3 65/100    -3  68/100     -3 60/100

-3.75     -3.65    - 3.68     -3.60

Least to greatest

-3.75          -3.68         - 3.65         -3.60   

-3  3/4     -3  17/25    -3  13/20     -3  3/5

Which statement MUST be true given that a, b, c, and d are all integers, and a < 0 < b < c < d?

1/a  > b     1/a  is negatve   b is positive    so.....   false

b - a > c  - a      add  a to both sides   b > c      so......      false

-a > c           not necessarily true   ....if a  = -1   and c = 5.......this is false

a > - d       if a  = -1    and d  = 1/2  then   -1 > -1/2  ???   false

c + a < d + a     subtract a from both sides   c < d     which is true