I know the answer I believe
I started by breaking 2010^2 into ist prime factors, 2*3*5*67 *2*3*5*67
Now 67*67 probably needs to be in one of the numbers 67*67=4489
I might as well knock over as many factors as possible with the first number so I will times that by 2
So my first number is 8978 that takes care of 3 of the factors
Now I need 5 and 5 to be factors so I need 8990 or better still 8975 that will take care of 5*5 both at the same time
So i have
8975, to 8978 That is 4 numbers.
How many factors will that take care of?
What factors still need to be included,
What is the best way of doing it.
What is the answer?