CPhill

3/2 ≤ (9/2)q-18      multiply throgh by 2

3 ≤ 9q - 36     add 36 to both sides

39 ≤ 9q      divide both sides by 9

39/9 ≤ q

13/3 ≤ q      is the same as   q  ≥ 13/3

I  = P * r * t    so

I  = 600 * .06 * 3   =  £ 108

Probably not....but we can use Google Translate.....

Наверное, нет .... но мы можем использовать Google Translate 

Well....that's better than the alternative.......!!!!

OK, H7....quit showing off...you're making me look bad....LOL!!!!

{ Actually....you're getting pretty good at this stuff ]

Let 3n be the first number, 3n + 3  be the second number and 3n + 6 be the third number....then....

3n + [3n+ 3] + [ 3n + 6]  = 36    simplify

9n +  9  = 36     subtract 9 from both sides 

9n =  27    divide both sides by 9

n = 3

So.....the first number 3(3)   = 9     tjhe second = 3(3) + 3  =  12     and the last = 3(3) + 6  = 15

And   9 + 12 + 15 =  36

So...the greatest number is 15

Good calc1....and you????

Very nice, H7.....!!!!!....5 points from me.....

-6(x-7) = -2(4+3x)     simplify on both sides

-6x + 42   = -8 - 6x    

-6x + 42  = -6x - 8

There is no solution to this because adding 42 to -6x can't possibly equal the same thing as subtracting 8 from -6x

1.   7x - 5

2.   2(x - 8)