CPhill

Here's an addendum to this :

Let a  = m      and  [ 2b + 3c]  =  n

So we are looking for the term in (m + n)^6  where  a = m has a power of 1....and this is given by

C(6,1) mn^5  =  6an^5

So....we have

6a [ 2b + 3c]^5

And now we are looking for the term in (2b + 3c)^5  where  [2b]  has a power of 2....and this is given by:

C(5, 2) [2b]^2 [3b]^3  =   10 * 4b^2 * 27c^3  =  1080 b^2 c^3

Putting this all together, the term we are looking for is given by

6a [ 1080 b^2 c^3]  =   6480ab^2c^3 .......   and 6480  is the coefficient

4x - 3 + 2x = 8x -3 -x   simplify

6x  - 3   =   7x   - 3       add 3 to both sides

6x  = 8x         subract  8x from both sides

- 2x  = 0      divide both sides b  - 2

x =  0

I assume you mean 348 plus 25% of 348   =   348 (1 + .25)  = 435

34*15/4=

[34 * 15] / 4  =

510 / 4  =

255 / 2 =

127.5

HEHEHEHE......!!!!!

Hit the  "2nd" button.......you will see asin, acos, etc......

28  =    2 x 2 x 7

66 =     2            x 3   x 11

GCF  =  2

See if this makes sense, amnesia  :

With the wind.....the plane covers  (D/60)  every minute  and against the wind, the plane covers (D/90)  every minute.....where D is the total disance beween the cities

So......the  average rate per minute  [ assuming no wind ] is given by  :

[D / 60  + D / 90]  / 2   =

[90D + 60D] / [ 60 * 90 *2]  =

[150D]  / [ 10800]  =

[15D ] / 1080]  =

D/72  ...... means that the plane would make the flight in  a normal time of 72 minutes witn no wind

Thus....the plane is 90 − 72   = 18 min late

Happy B'Day, HSC.......that cake does look good.....!!!!

4 x 4   =  16  outfits