CPhill

Happy New Year to everyone on Web2.0Calc......!!!!!

Melody got me a "mod−ship"......I'm not sure that intellligence had much to do wih it.....

438  = [n / 2] [ 40 + ( n − 1 ) 4 ]

876   =   [n] [40  + ( n − 1 ) 4 ]

876  = n [ 40 + 4n − 4 ]

876  =  n [ 36 + 4n]

876  = 36n + 4n^2

219  = 9n + n^2

n^2 + 9n  −  219  = 0

n  =  [  −9 ± √ 957 ] / 2

4(x-3)-8=16             simplify on the left

4x  − 12  − 8   =  16  

4x  − 20   =   16     add 20 to both sides 

4x  =   36     divide both sides by 4

x  = 9

See this :  http://ancienthistory.about.com/od/abacus/a/BabylonianMath.htm

16 possible outcomes

P         N           D           Q                     Value  of Heads

H        H           H           H                        .41

T        H           H           H                        .40

T        T           H            H                        .35

T        T           T            H                        .25

T        T           T           T                            0

H       T            T           T                         .01

H       H           T            T                        .06

H      H            H            T                        .16

T       H           T            T                         .05

T      T            H            T                         .10

H      T            T            H                         .26

T      H           H             T                         .15

T      H           T             H                         .30

H     T            H            T                          .11

H     T            H            H                          .36

H     H           T             H                          .31

P ( 15 cents or more of heads)  = 10/16 =  5/8

I get a little different answer from Ninja

Possible teams :

Team 1 : Bob is on the team and we can pick any 4 of the other 10 players [not counting Yogi ]  = C(10,4) = 210 possible teams

Team 2 :  Same as team 1 except that Yogi is on the team and we can pick any 4 of the other 10 players [not counting Bob ]  = C(10,4) = 210 possible teams

Team 3 :   Neither is on the team and we can pick any 5 of the other 10 players   = C(10,5) = 252 possible teams

So....the total teams, if the starting lineup can't contain both/either Bob and Yogi  = 2 * 210  + 252   = 672

Note.....the only remaining team is the one where both are on it and we can pick any 3 of the other 10 players  = C (10,3)   =  120

So all possible .teams = .....672  + 120  = 792   =  C(12,5)

Another approach

We have 15 ways to choose a goalie.....and for each of these, we can pick any 6 of the other 14 remaining people....so......the total  ways of choosing a team  =   

15 * C(14,6)   = 15 * 3003 =   45,045 ways

OK.....what's the question....???

5.35   = 

5 +  35 / 100  =

5 +  7 / 20