4 / [x (x + 2) ] = A / x + B / [x + 2]
4 / [x (x + 2)] = [ A(x + 2) + Bx] / [ x (x + 2))]
Since the denominators are the same, we can solve for the numerators
4 = A(x + 2) + Bx
4 = Ax + 2A + Bx
0x + 4 = (A + B)x + 2A
Equating coefficients, we have
(A + B) = 0
2A = 4 → A = 2
So ( A + B) = 0
2 + B = 0 → B = - 2
So....
4 / [x (x + 2) ] = 2 / x - 2 / [x + 2]
