CPhill

Thanks for that well-presented answer......and......welcome to the forum.....!!!

This refers to distinct hands....."Distinct Hands" is the number of different ways to draw the hand, not counting different suits

For instance.....there is 1 "distinct" royal flush......but there are  4 suits of them......

Clearly....there are WAY more than 858 two-pair hands......

Check the probability.....  123552/ 2598560   = about 4.75%

This says out of 2,598,560 possible hands, there are 123,552 hands consisting of two pairs....

Sorry, Melody...I believe this question  asks how many two-pair hands are possible in a draw of 5 cards....if I'm interepreting this correctly.....I think my answer is the only correct one....

Look at the number of possible royal flushes in the table......4....!!! 

Notice that "a" could come first and be matched with 25 letters  {the rest of them} for a total of 25 words

'b' could come first and be matched with 24 letters for a total of 24 words

"c" could come first and be matched with 23 lettters for a total of 23 words

etc........

So....this appears to just be the sum of the first 25 integers = [26 * 25] / 2  = 325

Hey....Melody and I agree on something!!!

Poker probabilities.....

I'm not sure as to what the correct answer might be......yours may be good.......!!!

Got it...it's like the number of identifiable five-letter words that can be formed when 3 of the letters are the same....

Thanks, Melody.....!!!

OH NO!!!.....It's the dreaded "Octagon" again.....!!!!

Hey....where is that border around it????

Did you steal it, Melody???

Melody, could you elaborate a little more on your answer??.....I'm having a "CDD" moment on this one....!!!!