CPhill

I'll take the American......looks like we're gonna' need a lot of cookies for that !!!

Geno....doesn't this come from the Indian mathematician, Ramanujan ???

I seem to remember [from Calculus class]   that he showed  that the same series could have different sums according to the arrangement of the series........

Only if you supply the milk, Melody   ........!!!!!

√9160  = √[916 * 10]  =√[458* 2 * 2 * 5]  = √[229 * 2 * 2 *2 *5] = √[229 *4 *2 *5]  = 2√[229*10]=

2√2290

5/6 - 1/4       get a common denominator of 24 ....  so we have.....

(4/4)(5/6)  -  (6/6)(1/4) =

20/24  - 6/24  =

14/24   =  7/12

x/4+x/(x-4)=4/(x-4)     subtract  x/(x -4) from both sides

x/4  = 4/(x-4) -  x / (x - 4)

x/4 = (4 - x) / (x -4)    factor out a negative in the numerator on the right

x/4 = -(x - 4)/ (x -4)          [note....   -a/a  = -1]

x/4 = -1      multiply both sides by 4

x = -4

"n"  = [ the number of terms in a row - 1 ]   ... So, we are expanding  (1 - 2x)^6

The 4th term is given by  C(6,3)*(-2x)^3  = 20 * (-8x^3)  =  -160x^3

Do they look like this  ???

2x^2 + 3xy – 4y^2 when x = 2 and y = - 4  .....  "plugging in,"  we have  ......

2(2)^2 + 3(2)(-4) - 4(-4)^2  =

2*4  + (6)(-4) - 4(16) =

8 - 24  -  64   =

-16 - 64   =

-80