Area = pi x r^2
area/pi = r^2
sqrt(area/pi) = radius
As before ...anywhere the denomintor = 0 the fxn is undefined
denominator = (x+3)(x-1) so when x = -3 or +1 the function is undefined.
....Excellent question Chris.....I hope some forum member with an advanced baking degree can answer it ! LOL
You are welcome SA....this question has been answered THREE times now....I hope you have looked at it by now !
G'Day !
(x-3) (x-3)/[(x-3)(x+10)] = 1 /(x+10)
_____ =
x^2 +7x-30
So as x approaches -10 you will have an asymtope there at -10 One asymtope at x = -10
7(y-4)-7 = 0
7y -28 -7 = 0
7y - 35 = 0
7y = 35
y = 5
7 x 9/6 x 3/10 = 63/6 x 3/10 = 189/60 = 3 9/60 = 3 3/20
http://web2.0calc.com/questions/when-a-15-newton-force-is-applied-to-on-end-of-a-lever-100-cm-long-a-60-newton-weight-is-attached-to-the-opposit-end-is-lifted-what-is-the-length-of-the
(4c+14c) -5 = 64
18c = 64+5
c = 69/18 = 23/6 = 3 5/6
This was posted and answered yesterday....see previous post.
