answer to heureka's comment=
8 also divides 64
you may argue that 4, 2, 1 also divides 64
but i have already proved it above
answer to melody's comment=
when we take 8 common from (nc08^n +nc18^n-1 + ...........+ncn8^0) we get (nc0^8n-1,nc18^n-2....)
for eg- 8 common from (1(nc08^n) we get= 8(8^n-1)
nc18^n-1=8(nc18^n-2) etc
remaining same
what do you think
please reply back
exams are approaching
and binomial theorem carries 90 marks