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if n belongs to natural numbers then the highest integer m such that 2^m divides (3^2n)9-8n-9

 Jan 5, 2016
 #1
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Hi Aditya,

 

if n belongs to natural numbers then the highest integer m such that 2^m divides (3^2n)9-8n-9

 

\((3^{2n})\times9-8n-9\\ \)

Is this what that expression is supposed to be?

 Jan 5, 2016
 #2
avatar+128 
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yes melody, sorry i dont know your name.

please try and tell me the answer

 Jan 5, 2016

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