Alan

Alternatively, you could plot a graph:

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First rewrite this as follows:

Multiply through by 3x + 2y

4 = -14(3x + 2y)

4 = -42x - 28y

Ad 28y to both sides and subtract 4 from both sides

28y = -42x - 4

Divide through by 28

y = -(42/28)x - 4/28  or y = -(3/2)x - 1/7

The slope of this line is -(3/2) so the slope of a line perpendicular to this is +(2/3)

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A:B means A/B, so

45/MOK = 3/2

Multiply both sides by MOK

45 = 3*MOK/2

Multiply both sides by 2

90 = 3*MOK

Divide both sides by 3

30 = MOK

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$$3.75\times 10^2=375$$

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I don't know what C scientific notation is, but just in ordinary scientific notation we have:

$$\\1300=1.3\times 10^{3}\\\\123.45=1.2345\times 10^{2}\\\\0.00426=4.26\times 10^{-3}$$

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1 L of water has a mass of 1 kg, so the potential energy of 50 L of water 10 metres above the bucket is:

50*1*9.8*10 Joules = 4900 Joules

This is turned into the same amount of kinetic energy as it hits the bucket.

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Yep, definitely a touch of CDD on my part here!

Moment and Torque are essentially the same thing except that Torque is a movement force, while Moment is a static force.  Torque tends to be used when there is an axle or pivot to be turned around, while Moment tends to be used in essentially non-rotational situations, such as analysis of forces on a beam.

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Hmm!  Your first expression isn't right either Nauseated.

$$\\ \frac{1}{x}+\frac{1}{4x}=\frac{5}{12}\\\\\frac{4}{4x}+\frac{1}{4x}=\frac{5}{12}\\\\\frac{5}{4x}=\frac{5}{12}\\\\4x=12\\\\x=3$$

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You have given the right formula TJM!!!

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$$\\a^{3b}-1 = 63\\ a^{3b}=64\\(a^b)^3=64\\a^b=64^{\frac{1}{3}}\\a^b=4\\x=4$$

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