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If a^b=x and a^3b-1=63, find the value of x

Guest Feb 28, 2015

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$$\\a^{3b}-1 = 63\\ a^{3b}=64\\(a^b)^3=64\\a^b=64^{\frac{1}{3}}\\a^b=4\\x=4$$

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Alan  Feb 28, 2015
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 #1
avatar+26640 
+5
Best Answer

$$\\a^{3b}-1 = 63\\ a^{3b}=64\\(a^b)^3=64\\a^b=64^{\frac{1}{3}}\\a^b=4\\x=4$$

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Alan  Feb 28, 2015

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