If a^b=x and a^3b-1=63, find the value of x

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Guest Feb 28, 2015

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$\\a^{3b}-1 = 63\\ a^{3b}=64\\(a^b)^3=64\\a^b=64^{\frac{1}{3}}\\a^b=4\\x=4$

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Alan Feb 28, 2015

Alan · Answer 1 · 2015-02-28T08:10:28

$\\a^{3b}-1 = 63\\ a^{3b}=64\\(a^b)^3=64\\a^b=64^{\frac{1}{3}}\\a^b=4\\x=4$

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