The energy required to stretch the spring away from equilibrium by distance x is given by (1/2)kx^2, so, in this case:
(1/2)k(1.25^2 - 0.75^2) = 100
k(25/16 - 9/16) = 200
k = 200 N/m. (Since 25/16 - 9/16 = 1)
(Note that the energy is the integral of force with respect to distance here, as it becomes increasingly difficult to stretch the spring the further it is away from equilibrium).