Think of the planes as being at the vertices of a right-angled triangle, where the right-angle is where they intersect.
The initial distances of the two planes from the intersection point are x1 and x2 respectively, They have velocities v1 and v2.
Then the following four equations apply:
v1 = x1/2
v2 = x2/2
v2 = v1 + 100
x12 + x22 = 10002
Solve these simultaneous equations to find the velocities.