asinus

4+|6-2|+8^2/ 4+6*3+4^0=

\(4+|6-2| +\frac{8^2}{4}+6\times3+4^0=43\)

  ! \(Excuse \ me \ please, Melody!\)

If i have a triangle in which the only known side is the hypotenuse "c" and i know all of the angle values "\(\alpha,\beta,\gamma\)", how do you get the remaining sides "a and b"?

\(c:sin\gamma= a:sin\alpha=b:sin\beta\)

\(\large a=\frac{c\times sin\ \alpha}{sin\ \gamma}\)

\(\large b=\frac{c\times sin\ \beta}{sin\ \gamma}\)

  !

y^-3

---------

x^-2

\(\LARGE\frac{y^{-3}}{x^{-2}}=\frac{x^{2}}{y^{3}}\)

  !

y^-3

---------

x^-2

\(\LARGE\frac{y^{-3}}{x^{-2}}\) \(\LARGE=\frac{\frac{1}{y^3}}{\frac{1}{x^2}} \) \(\LARGE= \frac{x^2}{y^3}\)

   !

f(x)=-2x^2+8x+25

\(f(x)=2x^2+8x+25\)

             a         b         c

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

\(x = {-8 \pm \sqrt{8^2-4*2*25} \over 2*2}\)

\(x= -2\pm\sqrt{-136}\)

\(x_1=-2+11.662\ i\)

\(x_2=-2-11.662\ i\)

   !

whats 18 square rooted

\(\sqrt{18}= \sqrt{2*3^2}=3\times \sqrt{2}\)

\(= 4.2426406871\)

  !

Write the following expression as a function of a positive acute angle. sin 200

Degree

\(sin 200°=-sin(200°-180°) \)

\(sin200°=-sin20°=-0.342020143326\)

rad

\(sin200=-sin(2\pi-(200-62\pi))\)

\(sin\ 200=-sin\ 1.06192983018 =-0.873297297\)

  !

5/9+4 1/6- 15

\(\frac{5}{9}+4\frac{1}{6}-15 \)   \(least \ common \ multiple= 18\)

\(=\frac{10+75}{18}-15\)

\(=4\frac{13}{18}-15\)

\(=-\frac{185}{18}\)

\(\frac{5}{9}+4\frac{1}{6}-15 \) \(=-10\frac{5}{18}\)

  !

19 volts 4.47 ampere =

\(P=U\times I \)    

\(P=19V\times4.47A=84.93\ W\)

  !

Thanks Alan and Guest for the right anser!

asinus   !