3,2,2 3 ways
3,4,1 6 ways
6,2,1 6 ways
In total there are 15 ways.
Using Simon's favorite factoring trick, we get (a-6)(b+5)=-16
If a is 4 and b 3, it satisfies the equation so the minimal value is 1.
First we need to pick the last digit. There are 2 choices as it must be odd.
The first two digits both have 4 choices as they can both be anything.
There are 6! ways to arrange 6 indistinguishable medals. But some are indistinguishable so we have to divide by them. 6!/(2!2!2!)=90
Let's call the number x. (3x+4)/4=x-3
Multiply by 4. 3x+4=4x-12
Combine like terms. x=16
Please explain. I'm looking for how to do it.