Use casework.

3,2,2 3 ways

3,4,1 6 ways

6,2,1 6 ways

In total there are 15 ways.

6^3=216

15/216=5/36

:D

yep lol

Using Simon's favorite factoring trick, we get (a-6)(b+5)=-16

If a is 4 and b 3, it satisfies the equation so the minimal value is 1.

First we need to pick the last digit. There are 2 choices as it must be odd.

The first two digits both have 4 choices as they can both be anything.

4*4*2=32

https://web2.0calc.com/questions/1-100-question

There are 6! ways to arrange 6 indistinguishable medals. But some are indistinguishable so we have to divide by them. 6!/(2!2!2!)=90

Let's call the number x. (3x+4)/4=x-3

Multiply by 4. 3x+4=4x-12

Combine like terms. x=16

Please explain. I'm looking for how to do it.