No, i do not think 1/3 is correct, but thanx for trying
Get me some chips, please
We have 3 choices for each ball, and each choice is independent. So 3^6 = 729 ways to place the b***s.
WRONG. im sorry, but WRONG. that would be the coorect answer for this problem though:
How many ways are there to put 6 b***s in 3 boxes if the b***s are distinguishable and the boxes are distinguishable?
now THAT would be 729.
wait, its 9 right? there are 3, so 3*3=9
oh yEah, you did
sure, any line will do
a) y=1x+3
b) y=1 & 1/2x+6
c)3y=-2/3x+2
sure ill help...
yay! hooray!!!
+1314 