A drawer contains 3 white b***s and 6 black b***s. Two b***s are drawn out of the box at random. What is the probability that they both are white?
the probability would be 1/3
No, i do not think 1/3 is correct, but thanx for trying
2/9
Assuming that we are drawing without replacement, we have :
P(Both White) = [Prob of white on first draw] * [ Prob of white on second draw] =
[3/9] * [2/8] = 6/72 = 1/12
+1313 
