BuilderBoi

We can write this problem as an equation: $11 \times 8.5 \times h = 140.25$.

In this equation, $h$ stands for the height of the $400$ papers. 

By solving for $h$, we find that the height is $1.5$ inches,

However, we are not done yet...

We need to account fot the fact that $h$ is the height of $400$ sheets of paper.

This means that the height for each paper is $1.5\over {400}$, which can be simplified to $\color{brown}\boxed {3\over{800}}$

A carry occurs when the place values have a sum $\geq10$. 

For the $1$'s digit, there are $7$ choices $(0,1,2,3,4,5,6)$

For the $10$'s digit, there are $4$ choices $(0,1,2,3)$

For the $100$'s digit, there are $5$ choices $(1,2,3,4,5)$. Remember, we can't use $0$ for the hundred's digit, because then the number wouldn't be 3-digits.

This means that there are $7 \times 4 \times 5$ numbers. Thus, the answer is $\color{brown}\boxed {140}$

I'm going to assume for this problem that the zarks are the zacks. If they are different, this problem can't be solved.

7 zacks = 1 zelk

14 zacks = 2 zelks

2 zacks = 6 zinks

14 zacks = 42 zinks

Thus... the answer is $\color{brown}\boxed{42\space\text zinks}$

For starters, $y=0$, because then $x=0$.

However, there is more than $1$ solution. 

Here is the work in LaTex:

$x+xy=250y$

$x=250y-xy$

$x=(250-x)y$

${x\over{250-x}} = y$

$x- {{x^2}\over{250-x}}=-240{x\over{250-x}}$

$x- {{x^2}\over{250-x}}={-240x\over{250-x}}$

$x={{-240x+x^2}\over250-x}$

$250x-x^2=-240x+x^2$ 

$490x=2x^2$

$245x=x^2$

$x=245$ 

Plug it in to the equation: 

$245+245y=250y$

$245 = 5y$ 

$y=49$

This means that the two answers are$\color{brown}\boxed {y=0,y=49}$

Simplify the first equation to $4x=-8-ay$.

Simplify the second equation to $3x=b+y$.

Multiply this equation by $4 \over 3$.

This equals $4x= {4 \over 3} b + {4\over3}y$.

For $4x=-8-ay$ and $4x={4\over3}b+{4\over3}y$ to have infinite intersection points, they have to be the same. 

So... $\color{brown}\boxed {a=-{3\over4}, b = -6}$

It is actually $37^ \circ$ Guest. This is $\angle GCE = \angle CBJ$. $\angle DBF$ is opposite to $\angle CBJ$, which means that $\angle DBF = \angle CBJ$. This means that $\color{brown} \boxed {\angle ECG = 37^\circ}$

The two equations are: $y = 2x+1$ and $y - 3 = 2x - 2$. The first one is already in slope-intercept form, but the second one is not. We can simplify the second one to $y= 2x+1$. Because the $2$ equations are identical, they intersect at an $\infty$ amount of points. This means that $\color{brown}\boxed {t = \infty}$

Let's call the unknown number $x$. By subsituting, we have $(7t-10)(3t+x)$. If we simplify this equation, we get $21t^2+7tx-30t-10x$. 

A binomial must have exactly $2$ terms, so $7tx-30t$ will have to equal $0$. 

The only way this can be possible is if $\color{brown} \boxed {x=4 {2\over 7}}$

The sum of the angles in a convex polygon is $180\times(s-2)$. If we use $4560$ as the sum of all the angles in the polygon, we have the equation $180\times(s-2)=4560$. This simplifies to $s=82/3$. Now, we have to round up, meaning that there is $\color{red}\boxed {28}$ sides in the polygon.

What's the figure?