BuilderBoi

We can write this problem as an equation: \(11 \times 8.5 \times h = 140.25\).

In this equation, \(h\) stands for the height of the \(400 \) papers. 

By solving for \(h\), we find that the height is \(1.5\) inches,

However, we are not done yet...

We need to account fot the fact that \(h\) is the height of \(400\) sheets of paper.

This means that the height for each paper is \(1.5\over {400}\), which can be simplified to \(\color{brown}\boxed {3\over{800}}\)

A carry occurs when the place values have a sum \(\geq10\). 

For the \(1\)'s digit, there are \(7 \) choices \((0,1,2,3,4,5,6)\)

For the \(10\)'s digit, there are \(4\) choices \((0,1,2,3)\)

For the \(100\)'s digit, there are \(5\) choices \((1,2,3,4,5)\). Remember, we can't use \(0\) for the hundred's digit, because then the number wouldn't be 3-digits.

This means that there are \(7 \times 4 \times 5\) numbers. Thus, the answer is \(\color{brown}\boxed {140}\)

I'm going to assume for this problem that the zarks are the zacks. If they are different, this problem can't be solved.

7 zacks = 1 zelk

14 zacks = 2 zelks

2 zacks = 6 zinks

14 zacks = 42 zinks

Thus... the answer is \(\color{brown}\boxed{42\space\text zinks}\)

For starters, \(y=0\), because then \(x=0\).

However, there is more than \(1\) solution. 

Here is the work in LaTex:

\(x+xy=250y\)

\(x=250y-xy\)

\(x=(250-x)y\)

\({x\over{250-x}} = y\)

\(x- {{x^2}\over{250-x}}=-240{x\over{250-x}}\)

\(x- {{x^2}\over{250-x}}={-240x\over{250-x}}\)

\(x={{-240x+x^2}\over250-x}\)

\(250x-x^2=-240x+x^2\) 

\(490x=2x^2\)

\(245x=x^2\)

\(x=245\) 

Plug it in to the equation: 

\(245+245y=250y\)

\(245 = 5y\) 

\(y=49\)

This means that the two answers are\(\color{brown}\boxed {y=0,y=49}\)

Simplify the first equation to \(4x=-8-ay\).

Simplify the second equation to \(3x=b+y\).

Multiply this equation by \(4 \over 3\).

This equals \(4x= {4 \over 3} b + {4\over3}y\).

For \(4x=-8-ay \) and \(4x={4\over3}b+{4\over3}y\) to have infinite intersection points, they have to be the same. 

So... \(\color{brown}\boxed {a=-{3\over4}, b = -6}\)

It is actually \(37^ \circ\) Guest. This is \(\angle GCE = \angle CBJ\). \(\angle DBF \) is opposite to \(\angle CBJ\), which means that \(\angle DBF = \angle CBJ\). This means that \(\color{brown} \boxed {\angle ECG = 37^\circ}\)

The two equations are: \(y = 2x+1\) and \(y - 3 = 2x - 2\). The first one is already in slope-intercept form, but the second one is not. We can simplify the second one to \(y= 2x+1\). Because the \(2\) equations are identical, they intersect at an \(\infty\) amount of points. This means that \(\color{brown}\boxed {t = \infty}\)

Let's call the unknown number \(x\). By subsituting, we have \((7t-10)(3t+x)\). If we simplify this equation, we get \(21t^2+7tx-30t-10x\). 

A binomial must have exactly \(2\) terms, so \(7tx-30t\) will have to equal \(0\). 

The only way this can be possible is if \(\color{brown} \boxed {x=4 {2\over 7}}\)

The sum of the angles in a convex polygon is \(180\times(s-2)\). If we use \(4560\) as the sum of all the angles in the polygon, we have the equation \(180\times(s-2)=4560\). This simplifies to \(s=82/3\). Now, we have to round up, meaning that there is \(\color{red}\boxed {28}\) sides in the polygon.

What's the figure?