Given that $\overline{JD} \parallel \overline{EK}$, $\angle FBD = 37^\circ$, and $\angle ABG = 46^\circ$, find $\angle ECG$ (in degrees).
It is actually \(37^ \circ\) Guest. This is \(\angle GCE = \angle CBJ\). \(\angle DBF \) is opposite to \(\angle CBJ\), which means that \(\angle DBF = \angle CBJ\). This means that \(\color{brown} \boxed {\angle ECG = 37^\circ}\)