BWStar

Alrighty, @ElectricPavlov I guess you were feeling lazy cuz you don't usually do this so I'll finish for you ig.

sqrt(19)^2+9^2 = c^2

81+19 = c^2

100=c^2

c = 10

For all the AOPS students here, the solution is 1936. I turned it in and it said it was correct so have fun cheating!

Sorry, that was volume. The surface area is 30*8*2 + 12*8*2 + 30*12 + 9*12*2 + 11*12*2 + 12*12.

I will calculate the volume with the bottom box + upper box. 30*8*12 is the dimensions of the bottom box, and 11*(30-9-9)*12 = 2880+1584 = 4464

3)

The volume is about 3.5^2 *3.14(pi*r^2) because the diameter is 7cm so the volume is 3ish^2*3ish so the answer is 9^3 = 27

4)

You would need to know the area of a circle if you wanted to put a rocket into space, you would need to know how much fuel is in the tank

5)

a)

the radius is 2.3, so the answer is 2.3^2*pi = 5.29pi

b)

5.29pi/2 = 2.645pi

It is a curve because it doesn't grow at a constant rate, so each point is higher than the previous point. As an example try to graph the points yourself

5y-3=3y+27

2y-3=27

2y=30

y=15.

360 - 2y = 360-30 = 330

B = 330/2

B = 115

Since the board is a square the total area of the shape is 12*12 = 144. we know that the side length of the rectangle that was taken out was 10 because 2 feet of the board still remain. we know the height of the board taken out is 4, by looking at the picture, so the boards area is 144 - 40 = 104

assuming the question is in terms of pi, sqrt 64 = 8 meaning the radius is 8, and we don't need to worry about the height because the are similar. the second cylinder, 729 has radius of sqrt726 = 27. The scale factor is 8:27