What is the probability that two cards randomly selected from a standard 52 card deck are is a red card followed by a King if the first card is not replaced after it is drawn?
Split this into 2 scenarios, first, the probability of drawing a red king then a red card. Then, the probability of drawing a black king then a red card. Finally, add them together. :))
=^._.^=
I think you have the porblem backwards? We draw the red card first, so that may affect the probabilty of drawing a king after. How do I acount for this?
Ohh, I do have it backwards.
First, the probability of drawing a red card is 26/52 = 1/2.
2/52 of them are red kings.
24/52 of them are red cards.
If we start by drawing a red king, there are 3 kings left, 3/51. So the chance we draw a red king, then another king is 2/52*3/51.
If we start by dawing a red card that if not a king, there are 4 kings left, 4/51. So the chance we draw a red card (non king), then a king is 24/42*4/51.
Adding the chances together, 24/42*4/51 + 2/52*3/51. :))
Please tell me if there are any mistakes or questions.
=^._.^=