I like these kinds of questions
So, there's 7 where B, C, and P intersect (the middle).
If there's 12 people in B and C, and 7 of those are already in the BCP, then there's 12 - 7 = 5 people in B and C ONLY (The middle-top intersection), not P
If there's 15 people in B and P, and 7 of those are already in the BCP, then there's 15 - 7 = 8 people in B and P ONLY (The middle-left intersection), not C
If there's 20 people in C and P, and 7 of those are already in the BCP, then there's 20 - 7 = 13 people in C and P ONLY (The middle-right intersection), not C
If there's 35 people in the entire circle of B, and (7 + 5 + 8) = 20 are already in other regions too, then there's 35 - 20 = 15 people in B ONLY (The left huge area)
If there's 32 people in the entire circle of P, and (7 + 8 + 13) = 28 are already in other regions too, then there's 32 - 28 = only 4 people in P ONLY (The bottom huge area)
Now, for the remainder of C, we just add up the values we've already put in the venn diagram, and subtract that sum from the total number of students (60).
That sum is 7 + 5 + 8 + 13 + 15 + 4 = 52
60 - 52 = 8
Therefore, there are 8 people in C ONLY (The right huge area).
Hope you followed along :D
EDIT - forgot to do the other problem :( will make another answer