We can make \(4x+3y=3\) into \(y=mx+b\) form! We need to isolate \(y\) .
\(3y=-4x+3, y=-\frac{4}{3}x+1\)
However, the line goes through (2, 3) so the y-intercept may not be 1! Let's substitute.
\(3=-\frac{4}{3}\times 2+b, 3=-\frac{8}{3}+b, b=17/3\) and m=-4/3.
You are very welcome!
:P
