CPhill

9ft 6in = 9.5 ft

So, 9.5 x 10 = 95 sq ft

So we have

95 sq ft x (1 sq yd / 9 sq ft) = (10+5/9) sq yd ≈ 10.55 sq yd

Kool-Aid......if you're going to "steal" answers....at least make them LOOK a LITTLE different from the original !!! Why would you do this??? I may sometimes present another way to find an answer, but I usually don't mimic the same approach given by others. This is known as "beating a dead horse".......

WolframAlpha shows two real solutions to this:

Let's convert the fat to Graham Cracker notation......(You may have to enable "cookies" on your browser to do this....)

Now....serve with a glass of milk.......(imperial minims amount varying by preference)

....And there you go......

Here's another way I like to do this kind of problem

Add

1/3 + 1/4 + 1/6 =

4/12 + 3/12 + 2/12 =

9/12     Now, take the reciprocal of this fraction 

12/9 =

4/3 =

1 + 1/3 hrs

We can write

log5832^1/3 =

(1/3)log 5832 =

(1/3)(3.765817515309918) =

1.255272505103306  ....... and we can write

10^{1.255272505103306}  = 18

So, assuming that 80 cm is the height of the first tank, the volume of water in the first tank =

40*20*80 = 64000cm^3

Note that the volume of water remains constant and is divided between the two tanks thusly:

40*20*h + 60*40*h = 64000   

800h + 2400h = 64000

3200h = 64000

 h = 20

So, both tanks would be filled to a height of 20cm

And the volume of water that would be poured from Tank A = 40*20*(80-20) =

48000cm^3

An empty tank has a capacity of 55.2 litres.Water flows from a Tap A at 3.6 litres per mimute and 2.4 litres per minute from a Tap B.Tap A was turned on first.Tap B was turned on 2 minutes later.The taps were turned off at the same time when the tank was completely filled without overflowing.How much water flowed from Tap B?

When B is turned on, A has put 3.6(2) = 7.2 litres of water into the tank. So there remain 55.2 - 7.2 = 48 litres to fill.  So we have:

3.6T + 2.4T = 48     where T is the time it takes to fill the rest of the tank  .......Simpifying, we have

6T = 48

T  = 8 minutes

So, since B was on for 8 minutes, it put 2.4(8) -= 19.2  litres into the tank.

-6 / (1/2) =

-6 x (2/1) =

-12