CPhill

(x-5)^2-72=0      add 72 to both sides

(x-5)^2  = 72      take the square root of both sides

x - 5  = ±√72

x - 5  = ±√(36 * 2) =

x - 5  = ±6√( 2)    add 5 to both sides

x = 5 ± 6√( 2)

415=5x^3    divide both sides by 5

83 = x^3      take the cube root of both sides

x = ³√83

-6 × 1 – (-15 + |4| × |6|)    simplifying, we have

-6 x 1  - ( -15 + 4*6)  =

-6 x 1  - ( -15 + 24)  =

[-6 x 1]  - ( 9)  =

-6 - 9   =

-15

Find the distance between all three points using the distance formula.....

Add all these results for the perimeter

To find the area of this triangle  ....let's use something called the "semi-perimeter"   = S  ...this is given by .....(A + B + C) / 2    where A, B and C are the side lengths

Then the area is given by....

√[S * (S - A) * (S - B) * (S - C)]

If you get stuck, let me know..........!!!

If we have, √x  - 8, then x ≥ 0 ⇒  [0, ∞ )

If we have √(x - 8), then x ≥ 8 ⇒  [8, ∞ )

Here's the "proof" of this......

Total Distance / Total Time = Average Rate

Let D be the one-way distance....then, the total distance = 2D

And the total time is given by    D/R₁ + D/R₂   ......so we have.....

[2D] / [ D/R₁ + D/R₂ ]  =

[2D] / [D (R₂ + R₁)/ (R₁R₂)] =

[2(R₁R₂)] / (R₂ + R₁) ........note that this doesn't depend on "D"

47 is a prime number........thus....this fraction cannot be reduced

26 + 5(7)   =

26 + 35  =

61 hrs.

16 / [q + 1] = 4      multiply both sides by q + 1

16 = 4[q + 1]          simplify

16 = 4q + 4            subtract 4 from both sides

12 = 4q                   divide by 4 on both sides

3 = q

It's always easy to find the average speed in these situations......here's the "formula"...

[2* R₁* R₂] / [R₁ + R₂ ]   ......where R₁ and R₂ are the two different rates.......