Notice one thing more about this one , if we want to use Melody's algebraic method....taking it from here
5(x-2)(x-4)2 < 3(x-2)2(x-4)
We can do this to simplify things.....
5(x-2)(x-4)2 - 3(x-2)2(x-4) < 0 factoring, we have
(x-2)(x-4)[5(x-4) - 3(x-2)] < 0
(x-2)(x-4)[5x- 20 -3x +6 ] < 0
(x-2)(x-2)[2x -14] < 0
2(x-2)(x-4)(x-7) < 0
(x-2)(x-4)(x-7) < 0
And notice that we don't have to use the Factor Theorem at all....the "roots" (i.e., critical interval values) are right in front of us !!!
