CPhill

LOL!!!!......the  second near-to-impossible figure.....here's  the first :

Rectangle -  a quadrilateral having 4  right angles

Thus....a square is a rectangle.....but a rhombus is not

-7pi/6  =  5pi/6

tan (5pi/6)  =  -1/sqrt (3) =  - sqrt (3) / 3

csc (pi/4)  =  sqrt (2)

cos (17 pi / 3)  =   cos (5pi / 3)  =  1/2

2sqrt (7) =  sqrt (28)

r =  sqrt  [ 5^2  + (sqrt (28))^2 ]  = sqrt  [ 25 + 28 ]  =  sqrt (53)

This is an angle in  Q2.....the cos  is  negative here....so.....

cos B  =  -5 / sqrt (53)  =  -5sqrt (53) / 53

True.....

See my answer, here  :

https://web2.0calc.com/questions/ep-melody-cphil-please-come

Thx, CPFB!!!!!

Glad we could "un-stump" you......

75  /  .60   =  125  cars  in the lot

When it hits the ground, h  =   0       ......so.....

-10t^2 + 10t + 60   = 0     multiply through  by   -1

10t^2  -10t  - 60    =  0           divide through  by 10

t^2  - t  -  6  =  0       factor

(t - 3) ( t + 2)   =   0

The  first factor set to 0  gives  us what we need

t  - 3  =   0

t  =   3  (seconds to hit the ground)

y = kx

12 = k * 8

12/ 8   =  k   =  3/2

So....when  x =  9  

y  = (3/2) (9)

y =   27 / 2   =  13.5