Let the angle formed by the triangle at Canton = C
And the angle formed by the triangle at Naples = 90 - 44 = 46°
sin (46 ) / 680 = sin C / 545
545 * sin ( 46 ) / 680 = sin C
arcsin ( 545 * sin (56) / 680 ) = C ≈ 35.2°
Draw a perpendicular from Elgin to the base of the triangle...call the point of intersection with the base, P
So let the triangle formed by P , C and the angle formed by the perpendicular at Elgin be PCE
So angle CEP = 90 - = 54.8°
This angle is supplemental to 180
The suplemental angle is 125.2°
In terms of bearing, the bearing from Elgin to Canton = 360 - 125.2 = 234.8° ≈ 235°
CORRECTED !!!!
