1. 3x^(2/3)+4x^(1/3)-4=0 I re-wrote this to what I think you meant
Factoring directly, we have
(3x^(1/3) - 2) (x^(1/3) + 2) = 0
Setting each factor to 0, we have
3x^(1/3) - 2 =0 add 2 to both sides
3x^(1/3) = 2 divide by 3 on both sides
x^(1/3) = 2/3 cube both sides
x = 8/27
And for the other factor, we have
x^(1/3) + 2 = 0
Subtract 2 from both sides
x^(1/3) = -2 cube both sides
x = -8
2. (1+1/x)^2 - 6(1+1/x) + 8 =0
We can factor this directly, too
[(1 + 1/x) - 4] [(1 + 1/x) - 2] = 0
Set each factor to 0
(1 + 1/x) - 4 = 0 add 4 to both sides
1 + 1/x = 4 subtract 1 from both sides
1/x = 3 divide by 3 and multiply by x on both sides
x = 1/3
And for the other factor, we have
(1 + 1/x) - 2 = 0 add 2 to both sides
1 + 1/x = 2 subtract 1 from both sides
1/x = 1 so x = 1
