Here's my contribution to this ....
The total arrangements for any 7 people sitting in a row is 7! = 5040
We can seat the 3 people together in five different ways.....(seats 1 - 5)
And for each of these there are 3! ways they can be arranged
So, the total number of ways they can sit together is:
(5 * 3!) = 30
So....the probability that they don't sit together is
1 - ( the probability they do sit together) =
1 - 30/5040 = 0.994047619047619 = about 99%
I don't know if this is correct......if anuone spots a flaw in my logic.....I'll be glad to know!!!
