danielr_ddrp

Yes, thanks

\(x-\frac{4}{-1}=x+4 \)

\(x+4=0 \)

\(x=-4\)

\(\sqrt{ {(\frac{249}{49})}^{2}}= \frac{249}{49} \)

\(m=\frac{\Delta Y}{\Delta X } \)

\(m=\frac{-6-(-7)}{3-(-3)}\)

\(m=\frac{1}{6}\)

\(\frac{1}{6} =\frac{y-(-7)}{x-(-3)}\)

\(\frac{x+3}{6}-7 = y\)

\(\frac{x-39}{6}= y\)

\(\sqrt{x+\sqrt{x-2}}=2 ===>> {(x+\sqrt{x-2})}^{1/2}=2 ==>>> (x+\sqrt{x-2})=4 ===>>>4-x =\sqrt{x-2}\)

\(4-x=\sqrt{x-2} ==>>>{(4-x)}^{2}=x-2==>>{4}^{2}-2*4*x+{x}^{2}=x-2\) 

\(16-8x+{x}^{2}=x-2====>>18-9x+{x}^{2}=0\)

Applying Bhaskara we gonna have x=6 or x=3

And 

\(\sqrt{3+\sqrt{3-2}}=2\)

X=3

\(\sqrt{5^9}\)