Finding the equation for a line containing the points (3, -6) and (-3, -7).

$m=\frac{\Delta Y}{\Delta X }$

$m=\frac{-6-(-7)}{3-(-3)}$

$m=\frac{1}{6}$

$\frac{1}{6} =\frac{y-(-7)}{x-(-3)}$

$\frac{x+3}{6}-7 = y$

$\frac{x-39}{6}= y$

y=1/6x-1/2-6

y = 1/6x - (1/2+6)

y= 1/6x - 6 1/2

Thanks 

I think the first answer is what was wanted :)