DewdropDancer

Ah yes, I missed that part.

Well not everyone can answer your questions, just try them. Its not like you can just ask questions on a test... 

\(\sqrt[3]{x\sqrt{x}} =\sqrt[3]{x^{1+\frac{1}{2}}} =\sqrt[3]{x^{\frac{3}{2}}}\)

I already answered some of these questions, please stop posting these same problems and wait for someone to help you, or you can go ahead and do them yourself.

I think this is right...

19) There are 112 three digit numbers divisible by 8. 

12) For \(7^{2010}\) we have to multiply by 7 so this gives 49 for the last two digits. 

14) I memorized this: 3, 4, and 5 are lengths of a right triangle

15) \(\left(2^x\right)^2+2^x=12\)

\(\left(u\right)^2+u=12\)

\(u=3,\:u=-4\)

Thats a lot of questions, so I think you should at least try some of them, they aren't so hard. Just give them a try!

1)  There are 60 minutes in an hour, therefore 60 * 24 = minutes in a day and, 60 * 24 * 7 = minutes in a week, so 60 * 24 = 1440. and 60* 24 * 7 → 1440 * 7 = 10080 minutes in a week.

4)  

\(2^{10}\cdot \:4^{20}\cdot \:8^{30}=2^n\)

\(2^{140} = 2^n\)

\(\mathrm{True\:for\:all}\:x;\quad \:2^{140}=2^n\)

6) 

x = 12+1*x-2

x = 12 + x - 2

x = x + 12 -2

x = x+10

x - x = x + 10 - x

     0 = 10

No Solution

You have

30%:12

10%:4

10*10%:4*10

100%:40

So, the photographer took 40 pics

You can draw a picture if you need too

Both men walk 40 yards in opposite directions and then 30 yards to left.

The two men are standing on the ends of two triangles, if you use the pythagoras theorem,

we know that the distance between both of them is 100 yards.