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Two men stand back-to-back and walk in opposite directions for 40 yards each. Each of them then turns left and walks another 30 yards each. In yards, how far are the two men from one another?

 Jan 20, 2021
 #1
avatar+116126 
+1

To simplify this, let them start at (0,0)

 

Let  them  first walk east-west

 

Then   one is at  (40,0)   and the other is  at (-40,0)

 

Then...when each turn left and walk for  30 yars each.....one is at  ( 40,30)   and the other  is at ( -40, -30)

 

Using the distance  formula

 

D  =sqrt  [  (  40 -  - 40)^2   +  ( 30  -  -30)^2   ]=

 

sqrt [  80^2   + 60^2  ]  =

 

sqrt  [  6400 +  3600 ]  =

 

sqrt  [ 10000 ] =

 

100  yds apart

 

 

cool cool cool

 Jan 20, 2021
edited by CPhill  Jan 20, 2021
 #2
avatar+266 
+5

You can draw a picture if you need too

Both men walk 40 yards in opposite directions and then 30 yards to left.

The two men are standing on the ends of two triangles, if you use the pythagoras theorem,

we know that the distance between both of them is 100 yards.

 

cheekycheekycheeky

 Jan 20, 2021
 #3
avatar+33 
+2

Thanks!

 Jan 20, 2021
 #4
avatar
+1

To simplify this, let them start at (0,0)

 

Let  them  first walk east-west

 

Then   one is at  (40,0)   and the other is  at (-40,0)

 

Then...when each turn left and walk for  30 yars each.....one is at  ( 40,30)   and the other  is at ( -40, -30)

 

Using the distance  formula

 

D  =sqrt  [  (  40 -  - 40)^2   +  ( 30  -  -30)^2   ]=

 

sqrt [  80^2   + 60^2  ]  =

 

sqrt  [  6400 +  3600 ]  =

 

sqrt  [ 10000 ] =

 

100  yds apart

 

easy ✨✨✨😃

 Jan 21, 2021

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