+33 Two men stand back-to-back and walk in opposite directions for 40 yards each. Each of them then turns left and walks another 30 yards each. In yards, how far are the two men from one another?
+129852 To simplify this, let them start at (0,0)
Let them first walk east-west
Then one is at (40,0) and the other is at (-40,0)
Then...when each turn left and walk for 30 yars each.....one is at ( 40,30) and the other is at ( -40, -30)
Using the distance formula
D =sqrt [ ( 40 - - 40)^2 + ( 30 - -30)^2 ]=
sqrt [ 80^2 + 60^2 ] =
sqrt [ 6400 + 3600 ] =
sqrt [ 10000 ] =
100 yds apart
+240 You can draw a picture if you need too
Both men walk 40 yards in opposite directions and then 30 yards to left.
The two men are standing on the ends of two triangles, if you use the pythagoras theorem,
we know that the distance between both of them is 100 yards.
To simplify this, let them start at (0,0)
Let them first walk east-west
Then one is at (40,0) and the other is at (-40,0)
Then...when each turn left and walk for 30 yars each.....one is at ( 40,30) and the other is at ( -40, -30)
Using the distance formula
D =sqrt [ ( 40 - - 40)^2 + ( 30 - -30)^2 ]=
sqrt [ 80^2 + 60^2 ] =
sqrt [ 6400 + 3600 ] =
sqrt [ 10000 ] =
100 yds apart
easy ✨✨✨😃
