Suppose \(3b-4a = 24\). Given that a and b are consecutive integers, and b
Let's say that B is the larger integer. Then A would equal (B – 1) since they're consecutive.
Now it's just a substitution problem.
3B – 4A = 24
3B – (4 • (B – 1)) = 24
3B – 4B + 4 = 24
–B = 20
Therefore B = –20 and, since A = (B – 1), A = –21
Check answer by plugging values into original equation:
3 • (–20) – 4 • (–21) = (–60) – (–84) = +84 – 60 = 24 Answers check okay.
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