Ok. To solve the question, we start from x=1.
3−(x+2)=2x−2⇒3−(1+2)=2∗1−2
Now, do the parentheses in one side, and multiply in the other.
3−(1+2)=2∗1−2=3−(3)=2−2
Now, do subtraction from both sides.
3−(3)=2−2=0=0
We now know that the equation is true, so the answer is x=\begin{minipage}{0.9cm}\11\vspace{0.1cm}\end{minipage}
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