Average of 3 = $ 15
so price is 3*15 = $ 45 then add x
3*15 + x and divide by 4 to get the average = $ 16
(3*15 +x)/4 = 16
solve for x = $ 19
Well, first of all 100 000 / 50 000 000 = = . 00 2
so .002 > .9386.63523174
so x = 85.635 TIME periods each period is six hours
* 6 = 513 .81 hours = 21.4 days
sqrt (2x-4) = 1 + sqrt(x+5) square both sides
2x-4 = 1 + x + 5 + 2 sqrt(x+5) simplify
x -10 = 2 sqrt (x+5) square both sides
x^2 -20x+ 100 = 4x + 20 simplify
x^2 -24x+80 = 0 Factor ( or use quadratic formula)
(x-20)(x-4) = 0 x = 4 or 20
A rate = B rate = a
C rate = 12
1/12 + 1/a + 1/a = 1/3 solve for a
2/a = 3/12
a/2 = 12/3
a = 24/3 = 8 hrs
The discriminant portion of the quadratic formula = 0 for just one answer
b^2 - 4ac = 0 a = 1 b = -m c = (m-1)
m^2 - 4 ( 1)(m-1) = 0
m^2 - 4m + 4 = 0 quadratic formula shows m = 2
Expand R equation
x^2 + 2xy + y^2 = 121 sub in first equation
x^2 + y^2 + 2xy = 121
(61) + 2xy = 121
xy = 30 6 and 5 come to mind
Arrange line equation in the form y = mx + b m is the slope
y = -1/5 x+1 slope = -1/5 perpindicular slope = - 1/m = 5
y = 5x + b sub in the point given to find 'b'
-3 = 5(2)+b
b = -13
y = 5x-13
Use Quadratic Formula
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) a = 1 b=2 c= 5
\(x = {-2 \pm \sqrt{2^2-4(1)(5)} \over 2(1)}\) = .....................
It will drop the 10 m then it will become a geometric sequence
10 + 10 + 5 + 2.5 etc
10 + geometric sequance a1 =10 r = 1/2
sum of geometric sequence = a1 (1/(1-r))
= 10 (1 /1/2) = 20
10 + geometr seq sum = 10 + 20 = 30 m
In 20 minutes the helicopter will be 90 m/hr * 1/3 hr = 30 miles from origin
the x component will be 30 miles * cos 250
the y component will be 30 miles * sin 250 =........... miles
