Find the equation passing through (2,-3) that is perpendicular to the line x + 5y = 5.
Arrange line equation in the form y = mx + b m is the slope
y = -1/5 x+1 slope = -1/5 perpindicular slope = - 1/m = 5
y = 5x + b sub in the point given to find 'b'
-3 = 5(2)+b
b = -13
y = 5x-13