'Guest' question submissions are generally given lower priority....
Use distance formulat TWICE between 0, 0 and -4,6 and then again on -4,6 to 4,3
d^2 = (x1-x2)^2 + (y1-y2)^2
then add the 'd' s together.....
Given line slope , m = 3/2 perpindicular slope = - 1/m = -2/3
y = -2/3 x + b sub in the given point to calculate 'b'
6 = -2/3 (-12) + b shows b = -2
y = -2/3 x - 2
Still do not know what is being asked in this question AGAIN
(3 , 5/3 x)
(-6, -1/2 x) perhaps?
Perimeter 2l + 2w = 60
area l * w = 210 w = 210/l sub this into the first equation
2l + 2 * 210/l = 60
2l^2 -60l + 420 = 0 Use quadratic fromula to find l & w = 15 + sqrt15 and 15 - sqrt 15 cm
There are 36 possible rolls
5 x = 5 rolls
x 5 = 5 rolls
5 5 = 1 roll
11/36
First multiply 2 x * (5x-y+3) = 10x^2 - 2xy+6x
then multiply y * (5x-y+3) = 5xy - y^2 + 3y
then add the REDs together......
This is given -2 (x-3-sqrt5)(x-3+sqrt5) multiply it out and reduce by collecting like terms
and then you will see what A and B and C are
the 'x' of the vertex is then - B / 2A
use this value of 'x' in the equation to compute the 'y' value of the vertex.....
The shortest leg is th eone between 1,12 and 7,10
Use distance formula between to points to compute
(x1 -x2)^2 + (y1-y2)^2 = d^2
Cross multiply the L
sin^2 + 1 +2cos + cos^2 = 4 sin (1+cos) edited
2 + 2cos = 4 sin(1+cos)
2 = 4sin
1/2 = sin = 30, 150 degrees
1 oz is already missing + 38 oz = 39 ounces empty
39/50 x 100% = ........% empty
