Which equation represents the line that is perpendicular to y=3/2x+1 and passes through (-12,6)

Guest Jul 24, 2020

#1**+1 **

Given line slope , m = 3/2 perpindicular slope = - 1/m = -2/3

y = -2/3 x + b sub in the given point to calculate 'b'

6 = -2/3 (-12) + b shows b = -2

y = -2/3 x - 2

ElectricPavlov Jul 24, 2020